如何使用if條件檢查perl中的2個文件是否為空

if(-z "$file1" && "file2") {
 print "file1 and file2 are empty";
} else {
print "execute";
}

當我寫這個時，當文件為空時它會列印execute，當文件不為空時它會列印 file1 and file2 are empty。

當條件為真時，它應該列印file1 and file2 are empty，對嗎？還是錯了？

您缺少 a-z和$in -z "$file2"。此外，您不需要引用文件名（但這不會導致錯誤）。以 Perl 單行程式碼為例，執行以下測試：

rm -rf foo bar
touch foo
perl -le 'my $file1 = "foo"; my $file2 = "bar"; if ( -z $file1 && -z $file2 ) { print "file1 and file2 are empty"; } else { print "execute"; }'
# File 'bar' does not exist, so -z $file2 evaluates to false:
# execute

rm -rf foo bar
touch foo bar
perl -le 'my $file1 = "foo"; my $file2 = "bar"; if ( -z $file1 && -z $file2 ) { print "file1 and file2 are empty"; } else { print "execute"; }'
# Both files exist and are zero size, so both '-z' tests evaluate to true:
# file1 and file2 are empty

rm -rf foo bar
touch foo bar
echo '1' > bar
perl -le 'my $file1 = "foo"; my $file2 = "bar"; if ( -z $file1 && -z $file2 ) { print "file1 and file2 are empty"; } else { print "execute"; }'
# File 'bar' iz non-zero size, so -z $file2 evaluates to false:
# execute

引用自：https://unix.stackexchange.com/questions/622537