確定 makefile 配方的類型

我想確定使用者在 shell 中輸入的配方類型。但是下面的程式碼總是返回 false 。

all clean:    
ifeq ("$@", "clean")
       echo "This is an clean recipe"
else
   echo "This is not a clean recipe."
endif

您可以使用MAKECMDGOALS來獲取目標：

all clean:
ifeq ($(MAKECMDGOALS), clean)
 @echo "This is an clean recipe"
else
 @echo "This is not a clean recipe."
endif

$ make
This is not a clean recipe.
$ make clean
This is an clean recipe

引用自：https://unix.stackexchange.com/questions/627298