如何將目錄中的所有文件移動到另一個，但複製最新？

我正在嘗試編寫一個備份腳本，該腳本從目錄中移動所有文件，但只複製最新修改/最新的文件。

我遇到了一些麻煩，我無法返回正確的最新文件，因為我認為我無法通過修改獲取find或ls列出文件，並且只輸出文件名。所以我$latestfile最終成為一個不同的文件。

幫助？

我目前的程式碼：

# Primary Backup Location
BACKUP_LOCATION=/my/backup/dir

# List latest file
latestfile=$(find ${BACKUP_LOCATION} -maxdepth 1 -mindepth 1 -type f -exec basename {} \; | sort -nr | awk "NR==1,NR==1 {print $2}")

echo "Latest file is $latestfile"

# List all (EXCEPT LAST) files and get ready to Backup
echo "Backing up all files except last"
for file in $(find ${BACKUP_LOCATION} -maxdepth 1 -mindepth 1 -type f \! -name "$latestfile" -printf "%f\n" | sort -nr )
do
   echo $file
   #mv $file /some/target/dir/$file
done

想出瞭如何使這項工作。這是我的備份腳本的一部分，希望有人會發現它有用。

# Location to Backup from
BACKUP_TARGET="/my/dir/to/backup"
# Location to Backup to
BACKUP_LOCATION="/my/backup/store"

# List latest file
file_latest=$(find ${BACKUP_TARGET} -maxdepth 1 -mindepth 1 -printf '%T+ %p\n' | sort -r | head -n 1 | sed 's|.*/||' )
echo "Latest file is $file_latest"

# List the rest of files
file_rest_of_em=$(find ${BACKUP_TARGET} -maxdepth 1 -mindepth 1 -type f \! -name "$file_latest" | sed 's|.*/||' )

# make newlines the only separator
IFS=$'\n'

# Backup all previous Backups, MOVE ALL
echo "Backing up all files except Latest Backup..."
for file in $file_rest_of_em
do
   echo "Moving $file"
   mv -n ${BACKUP_TARGET}/$file $BACKUP_LOCATION/
done

# Backup Latest Backup, LEAVE COPY BEHIND
if [ -f "$BACKUP_LOCATION/$file_latest" ]; then
   echo "$file_latest (Latest Backup) already exists."
else
   echo "$file_latest (Latest Backup) does not exist."
   echo "Copying $file_latest..."
   cp -n --preserve=all ${BACKUP_TARGET}/$file_latest $BACKUP_LOCATION/
fi

# done with newline shenanegans
unset IFS

感謝您的幫助@Panki

引用自：https://unix.stackexchange.com/questions/621306