sed + 刪除“#”字元以防萬一出現行

我們有以下文件：

  cat graphite-web.conf

  #<IfModule mod_authz_core.c>
  #    # Apache 2.4
  #    Require local
  #    Order Allow,Deny
  #    Allow from All
  #    Require all granted
  #</IfModule>
  #<IfModule !mod_authz_core.c>
  #    # Apache 2.2
  #    Require all granted
  #    Order Allow,Deny
  #    Deny from all
  #    Allow from All
  #    Allow from ::1
  #</IfModule>

什麼是在“要求所有已授予”行之前刪除 # 的最佳方法

• “#”字元不在行首

預期輸出：

  #<IfModule mod_authz_core.c>
  #    # Apache 2.4
  #    Require local
  #    Order Allow,Deny
  #    Allow from All
       Require all granted
  #</IfModule>
  #<IfModule !mod_authz_core.c>
  #    # Apache 2.2
  #    Require all granted
  #    Order Allow,Deny
  #    Deny from all
  #    Allow from All
  #    Allow from ::1
  #</IfModule>

sed解決方案：

sed 's/#\([[:space:]]*Require all granted\)/ \1/' graphite-web.conf

輸出：

  #<IfModule mod_authz_core.c>
  #    # Apache 2.4
  #    Require local
  #    Order Allow,Deny
  #    Allow from All
       Require all granted
  #</IfModule>
  #<IfModule !mod_authz_core.c>
  #    # Apache 2.2
       Require all granted
  #    Order Allow,Deny
  #    Deny from all
  #    Allow from All
  #    Allow from ::1
  #</IfModule>

---

要就地編輯文件 - 添加-i選項：

sed -i ....

引用自：https://unix.stackexchange.com/questions/401276