如何為 7z 指定字元編碼？

在檔案上做7z x給我

'20 ª.1 ¯® '$'\302\212''¨à®¢®£à ¤áª ï ã«.rtf'  IMG_6527.JPG
''$'\302\212''¨à®¢®£à ¤áª ï, ¨áâ.doc'          IMG_6532.JPG
''$'\302\204''®¯  ᮣ« è¥­¨¥(3).doc'           IMG_6542.JPG
''$'\302\204\302\212\302\217''.doc'        IMG_6543.JPG IMG_6526.JPG

顯然，某些文件的編碼方式不同，7z預設情況下不會轉換為 UTF-8。如何告訴7z進行轉換？

我為字元集找到的唯一選項：

-scc{UTF-8|WIN|DOS}：為控制台輸入/輸出

-scs{UTF-8|UTF-16LE|UTF-16BE|WIN|DOS|{id}}設置字元集：為列表文件設置字元集

WIN, DOS,UTF-8不工作。當試圖通過猜測字元集時

7z -scsCP1251 l 26-08-2016_10-18-14.zip

7z 給出警告：

Unsupported charset: cp1251

unzip這樣做對嗎（西里爾符號已轉換）：

'20 к.1 по Кировоградская ул.rtf'  IMG_6532.JPG  'Доп  соглашение(3).doc'
26-08-2016_10-18-14.zip        IMG_6542.JPG  'Кировоградская, ист.doc'
IMG_6526.JPG               IMG_6543.JPG
IMG_6527.JPG               ДКП.doc

補充資料

• p7zip 版本：

15.14.1 (locale=ru_RU.UTF-8,Utf16=on,HugeFiles=on,64 bits,4 CPUs AMD Phenom(tm) II X4 960T Processor (100FA0),ASM)

• 歸檔開始的 hexdump ( od -tx1z -Ax):

000000 50 4b 03 04 14 00 00 00 00 00 81 54 1a 49 7e 35  >PK.........T.I~5<
000010 fa 34 00 ec 00 00 00 ec 00 00 07 00 17 00 84 8a  >.4..............<
000020 8f 2e 64 6f 63 75 70 13 00 01 19 fd 45 54 d0 94  >..docup.....ET..<
000030 d0 9a d0 9f 2e 64 6f 63 00 00 00 00 d0 cf 11 e0  >.....doc........<
000040 a1 b1 1a e1 00 00 00 00 00 00 00 00 00 00 00 00  >................<
000050 00 00 00 00 3e 00 03 00 fe ff 09 00 06 00 00 00  >....>...........<
000060 00 00 00 00 00 00 00 00 01 00 00 00 71 00 00 00  >............q...<
000070 00 00 00 00 00 10 00 00 73 00 00 00 01 00 00 00  >........s.......<
000080 fe ff ff ff 00 00 00 00 70 00 00 00 ff ff ff ff  >........p.......<
000090 ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff  >................<
*
000230 ff ff ff ff ff ff ff ff ff ff ff ff ec a5 c1 00  >................<
000240 07 80 19 04 00 00 f0 12 bf 00 00 00 00 00 00 10  >................<
000250 00 00 00 00 00 08 00 00 72 7b 00 00 0e 00 62 6a  >........r{....bj<
000260 62 6a 2a 16 2a 16 00 00 00 00 00 00 00 00 00 00  >bj*.*...........<
000270 00 00 00 00 00 00 00 00 19 04 16 00 34 8e 00 00  >............4...<
000280 48 7c 00 00 48 7c 00 00 4b 2c 00 00 00 00 00 00  >H|..H|..K,......<
000290 19 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  >................<
0002a0 00 00 00 00 00 00 00 00 ff ff 0f 00 00 00 00 00  >................<
0002b0 00 00 00 00 ff ff 0f 00 00 00 00 00 00 00 00 00  >................<
0002c0 ff ff 0f 00 00 00 00 00 00 00 00 00 00 00 00 00  >................<
0002d0 00 00 00 00 b7 00 00 00 00 00 3e 0e 00 00 00 00  >..........>.....<
0002e0 00 00 3e 0e 00 00 a0 1b 00 00 00 00 00 00 a0 1b  >..>.............<
0002f0 00 00 00 00 00 00 a0 1b 00 00 00 00 00 00 a0 1b  >................<
000300 00 00 00 00 00 00 a0 1b 00 00 14 00 00 00 00 00  >................<
000310 00 00 00 00 00 00 ff ff ff ff 00 00 00 00 b4 1b  >................<
000320 00 00 00 00 00 00 b4 1b 00 00 00 00 00 00 b4 1b  >................<
000330 00 00 38 00 00 00 ec 1b 00 00 84 00 00 00 70 1c  >..8...........p.<
000340 00 00 34 00 00 00 b4 1b 00 00 00 00 00 00 b8 28  >..4............(<
000350 00 00 e6 01 00 00 a4 1c 00 00 00 00 00 00 a4 1c  >................<
000360 00 00 00 00 00 00 a4 1c 00 00 00 00 00 00 a4 1c  >................<
000370 00 00 00 00 00 00 a4 1c 00 00 00 00 00 00 d8 1d  >................<
000380 00 00 00 00 00 00 d8 1d 00 00 00 00 00 00 d8 1d  >................<
000390 00 00 00 00 00 00 43 28 00 00 02 00 00 00 45 28  >......C(......E(<
0003a0 00 00 00 00 00 00 45 28 00 00 00 00 00 00 45 28  >......E(......E(<
*
0003c0 00 00 00 00 00 00 45 28 00 00 00 00 00 00 9e 2a  >......E(.......*<
0003d0 00 00 a2 02 00 00 40 2d 00 00 da 00 00 00 45 28  >......@-......E(<
0003e0 00 00 2d 00 00 00 00 00 00 00 00 00 00 00 00 00  >..-.............<
0003f0 00 00 00 00 00 00 a0 1b 00 00 00 00 00 00 d8 1d  >................<
000400 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  >................<
000410 00 00 00 00 00 00 d8 1d 00 00 00 00 00 00 d8 1d  >................<
000420

根據用於創建 zip 文件的編碼，您可以通過將語言環境臨時設置為“C”來防止不需要的翻譯：

LC_ALL=C 7z x $archive

（這有助於 IZArc 在 Win7 上使用您的兩個範例文件名創建的 zip。）

但是，對於問題中的存檔，“文件名”欄位包含“ДКП.doc”（84 8a 8f 2e 64 6f 63）的 CP1251 編碼。“額外”欄位使用 Info-zip 副檔名（參見Zip Specification v 6.3.4的第 4.6.9 節）來儲存 UTF-8 文件名。 unzip知道此標頭，並使用 UTF-8 名稱，忽略 CP1251 名稱。

7z對這個“額外欄位”不做任何事情，只使用 CP1251 之一。根據目前的語言環境，它可能會使用該確切名稱（原始字節84 8a 8f）創建文件，或者更糟的是，將它們視為 unicode 點以首先擴展為 UTF-8（c2 84 c2 8a c2 8f）。

一種選擇是使用外部實用程序來更改第zip一個：

#!/bin/bash

cp orig.zip renamed.zip

index=0
zipinfo -1 orig.zip | while read name ; do
       ziptool renamed.zip rename $index "$name"
       index=$((index+1))
done

ziptool來自libzip。 zipinfo與Info-ZIP 的 UnZip一起分發，因此您不妨使用unzip.

引用自：https://unix.stackexchange.com/questions/305886