快速殺死包含word的程序

$ ps aux | grep ruby
user              1565   3.7  0.1  4307464  17696 s000  S+    7:31AM   0:00.61 /Users/user/.rbenv/versions/2.3.1/bin/ruby bin/rails c
user              1579   0.0  0.0  4268020    788 s001  S+    7:31AM   0:00.00 grep ruby
user              1489   0.0  0.0        0      0   ??  Z     7:29AM   0:00.00 (ruby)

我如何快速殺死所有這些程序？

我嘗試了什麼：

kill -9 `ps aux | grep ruby`

我的環境：

$ bash --version
GNU bash, version 3.2.57(1)-release (x86_64-apple-darwin18)
Copyright (C) 2007 Free Software Foundation, Inc.
$ uname -a
Darwin MacBook-Pro.local 18.0.0 Darwin Kernel Version 18.0.0: Wed Aug 22 20:13:40 PDT 2018; root:xnu-4903.201.2~1/RELEASE_X86_64 x86_64
$

正如 Haxiel 評論的那樣，我的建議是使用pkill：

pkill -9 ruby

kill $(ps aux | grep ruby | grep -v grep | awk '{print $2}' | xargs)

for p in $(ps aux | grep ruby | grep -v grep | awk '{print $2}'); do kill $p; done

必要時可以代替kill9。kill

引用自：https://unix.stackexchange.com/questions/482996