使用 sed 解析 % 分數

我正在嘗試為我的 github ci 操作解析程式碼覆蓋率，我一切正常，但無法解析覆蓋率 % 結果。請幫我解析程式碼覆蓋率的百分比分數，我無法讓正則表達式工作：

命令

name: Pytest Coverage
on:
 pull_request:
   branches: [ main, dev ]
jobs:
 build:
   runs-on: ubuntu-latest
   steps:
   - uses: actions/checkout@v2
   - name: Set up Python 3.10
     uses: actions/setup-python@v2
     with:
       python-version: "3.10"
   - name: Install dependencies
     run: |
       python -m pip install --upgrade pip
       pip install flake8 pytest pytest-cov
       if [ -f requirements.txt ]; then pip install -r requirements.txt; fi
   - name: Build coverage file
     run: |
       pytest --cache-clear --cov=src tests/ > pytest-coverage.txt
   - name: Comment coverage
     uses: coroo/pytest-coverage-commentator@v1.0.2
   - name: Get Coverage %
     run: |
       LAST_LINE=$(tail -4 pytest-coverage.txt)
       LAST_LINE=$(head -n 1 <<< "$LAST_LINE")
       echo "target line is $LAST_LINE"
       COVERAGE=$(sed -n '$s/.*?\([0-9]+\)%.*/\1/p' <<< "$LAST_LINE")
       echo "overall coverage is $COVERAGE"

$LAST_LINE 是

TOTAL                                               2401   1538    36%

$COVERAGE 目前為空白，預期輸出：

36%

使用sed

COVERAGE=$(sed 's/.*[[:space:]]\([0-9]\+%\)/\1/' <<< "$LAST_LINE")

刪除最後一個空白字元（空格或製表符）之前的所有內容：

$ sed 's/.*[[:blank:]]//' file
36%

用於awk列印最後一個以空格分隔的欄位：

$ awk '{ print $NF }' file
36%

或者，作為程式碼的一部分（假設只有一行以字元串開頭TOTAL

COVERAGE=$( sed -n 's/^TOTAL.*[[:blank:]]//p' pytest-coverage.txt )

這直接從 中提取百分比pytest-coverage.txt，而無需呼叫heador tail。

引用自：https://unix.stackexchange.com/questions/690810