Shell-Script
在單個命令中使用兩個分隔符從 awk 獲取結果
僅 ping 命令的輸出：
[root@servera ~]# ping -c 4 8.8.8.8 PING 8.8.8.8 (8.8.8.8) 56(84) bytes of data. 64 bytes from 8.8.8.8: icmp_seq=1 ttl=128 time=8.04 ms 64 bytes from 8.8.8.8: icmp_seq=2 ttl=128 time=7.47 ms 64 bytes from 8.8.8.8: icmp_seq=3 ttl=128 time=7.72 ms 64 bytes from 8.8.8.8: icmp_seq=4 ttl=128 time=7.50 ms --- 8.8.8.8 ping statistics --- 4 packets transmitted, 4 received, 0% packet loss, time 3007ms rtt min/avg/max/mdev = 7.473/7.683/8.037/0.225 ms我只想從“收到的 4”中擷取整數 4。
ping -c 4 8.8.8.8 | awk -F ',' '/received/ { print $2 }'結果是
4 received。我只想從上面的命令中擷取數字 4。我怎樣才能做到這一點？分隔符現在是空格。
所有你需要的是：
awk '/received/{print $4}'例如，
cat file用於獲得與awk您的問題相同的輸入：$ cat file PING 8.8.8.8 (8.8.8.8) 56(84) bytes of data. 64 bytes from 8.8.8.8: icmp_seq=1 ttl=128 time=8.04 ms 64 bytes from 8.8.8.8: icmp_seq=2 ttl=128 time=7.47 ms 64 bytes from 8.8.8.8: icmp_seq=3 ttl=128 time=7.72 ms 64 bytes from 8.8.8.8: icmp_seq=4 ttl=128 time=7.50 ms --- 8.8.8.8 ping statistics --- 4 packets transmitted, 4 received, 0% packet loss, time 3007ms rtt min/avg/max/mdev = 7.473/7.683/8.037/0.225 ms$ cat file | awk '/received/{print $4}' 4顯然只是替換
cat file為ping -c 4 8.8.8.8您的真實測試。回應下面的 OP 評論，詢問它在哪一行匹配：
$ awk '/received/' file 4 packets transmitted, 4 received, 0% packet loss, time 3007ms以及為什麼要列印第 4 個欄位：
$ awk '/received/{for (i=1; i<=NF; i++) print i, "<" $i ">"}' file 1 <4> 2 <packets> 3 <transmitted,> 4 <4> 5 <received,> 6 <0%> 7 <packet> 8 <loss,> 9 <time> 10 <3007ms>