使用 sed 將空行及其下方的一行替換為 <tag>

我有這樣的東西；

One blank line below

> This is a text
> This is another line of text

One blank line above

試圖得到這樣的東西；

One blank line below

<blockquote>
> This is a text
> This is another line of text
</blockquote>

One blank line above

試過這個；

sed 's/^\n\(>\)/\r<blockquote>\r\1/g' test.txt

and

sed 's/^\(>.*\)\n$/\1\r<\/blockquote>\r/g' test.txt

當我在 vim (8.1) 中時，這些正則表達式對我來說工作得很好，但是，當我從我的 shell(bash) 中嘗試它時，我沒有看到任何結果。當我從 shell 執行這些時，似乎什麼都沒有改變。我在哪裡錯了？

我會用awk狀態機來做這個。我使用標誌blank並block表示一個空行和一個塊

awk '
   /^$/ { blank++ }                                            # Blank line
   blank && /^>/ { blank=0; block++; print "<blockquote>" }    # First ">" line after blank
   block && blank { block=0; print "</blockquote>" }           # First blank after ">"
   /^./ { blank=0 }                                            # Non-blank line
   { print }                                                   # Print the input data
'

測試數據

One blank line below

> This is a text
> This is another line of text

One blank line above

------------------------------------

One blank line below
> This is a text
> This is another line of text
One blank line above

------------------------------------

One blank line below

> This is a text

> This is another line of text

One blank line above

輸出

One blank line below

<blockquote>
> This is a text
> This is another line of text
</blockquote>

One blank line above

------------------------------------

One blank line below
> This is a text
> This is another line of text
One blank line above

------------------------------------

One blank line below

<blockquote>
> This is a text
</blockquote>

<blockquote>
> This is another line of text
</blockquote>

One blank line above

引用自：https://unix.stackexchange.com/questions/645108