在深度嵌套的 JSON 中為特定鍵名選擇特定的所有鍵路徑和值

我有一個非常大的半結構化 JSON 模式，嵌套單元結構由一個鍵標記：“ObjectType”以指示一些有意義的資訊。

我正在嘗試使用 jq 來選擇所有這些 ObjectType(s) 及其值的路徑。

json的範例部分是：

{
   "ObjectType": "ClassZ",
   "LastModifiedBy": "janeroe",
   "Name": "Anonymous",
   "ArrayProps": [],
   "Logistics": [
     {
       "ObjectType": "ClassA",
       "Source": "Vendor",
       "UUID": "x868-dhibye9-7678-12",
       "EffectiveDate": "2020-01-01",
       "Active": true,
       "Preferred": 0
     }
   ],
   "IsVirtual": true,
   "Convention": 3,
   "CruiseParams": [
     {
       "ObjectType": "ClassB",
       "Destinaton": "Atlantis",
       "Value": "3"
     }
   ],
   "InvolvedParties": [],
   "PartyEvents": [
     {
       "ObjectType": "ClassC",
       "CreatedDate": "2020-01-01",
       "CreatedBy": "johndoe"
     }
   ],
   "FunFactors": [
     {
       "ObjectType": "ClassD",
       "Level": 1
     }
   ]
 }

試圖輸出類似或接近的東西：

"ObjectType":                "ClassZ"
"Logistics/0/ObjectType":    "ClassA"
"CruiseParams/0/ObjectType": "ClassB"
"PartyEvents/0/ObjectType":  "ClassC"
"FunFactors/0/ObjectType":   "ClassD"

這是我能想到的最好的方法，基於如何使用 jq 獲取找到的值的索引路徑？

$ jq -rc 'paths as $p | select($p[-1] == "ObjectType") | "\($p|@csv): \"\(getpath($p))\""' sample.json
"ObjectType": "ClassZ"
"Logistics",0,"ObjectType": "ClassA"
"CruiseParams",0,"ObjectType": "ClassB"
"PartyEvents",0,"ObjectType": "ClassC"
"FunFactors",0,"ObjectType": "ClassD"

引用和定界並不完全符合您的要求 - 使用您map(tostring)| join(“/“)從評論中提出的建議，它變成

$ jq -rc 'paths as $p | select($p[-1] == "ObjectType") | "\"\($p|map(tostring)|join("/"))\": \"\(getpath($p))\""' sample.json
"ObjectType": "ClassZ"
"Logistics/0/ObjectType": "ClassA"
"CruiseParams/0/ObjectType": "ClassB"
"PartyEvents/0/ObjectType": "ClassC"
"FunFactors/0/ObjectType": "ClassD"

引用自：https://unix.stackexchange.com/questions/565147