執行命令 x 秒？

可能重複：

在指定時間內執行命令，如果時間超過則中止

是否有一個命令允許我最多執行另一個命令 x 秒？

想像的例子：runonlyxseconds -s 5 <the real command and its args>

之後它將被強制終止（例如，第一次發送SIGTERM，如果它不起作用，SIGKILL）。

謝謝

bash僅使用幾乎普遍可用的系統命令的純解決方案：

timeout() {
   if (( $# < 3 )); then
       printf '%s\n' 'Usage: timeout sigterm-seconds sigkill-seconds command [arg ...]'
       return 1
   fi

   "${@:3}" &
   pid=$!

   sleep "$1"

   if ps "${pid}" >/dev/null 2>&1; then
       kill -TERM "${pid}"
       sleep "$2"
       if ! ps "${pid}" >/dev/null 2>&1; then
           printf '%s\n' "Process timed out, and was terminated by SIGTERM."
           return 2
       else
           kill -KILL "${pid}"
           sleep 1
           if ! ps "${pid}" >/dev/null 2>&1; then
               printf '%s\n' "Process timed out, and was terminated by SIGKILL."
               return 3
           else
               printf '%s\n' "Process timed out, but can't be terminated (SIGKILL ineffective)."
               return 4
           fi
       fi
   else
       printf '%s\n' "Process exited gracefully before timeout."
   fi
}

然後執行為timeout sigterm-seconds sigkill-seconds command [arg ...].

引用自：https://unix.stackexchange.com/questions/30621